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Solving by Factoring

To solve a quadratic equation like x2+5x+6=0x^2 + 5x + 6 = 0 by factoring, we want to rewrite the trinomial as a product of two simpler linear . We are essentially reversing the multiplication process to find the constituent parts. We need to find two numbers that multiply to our constant term (66) and add up to our middle coefficient (55). The numbers 22 and 33 fit perfectly because 2×3=62 \times 3 = 6 and 2+3=52 + 3 = 5. This lets us rewrite the equation as (x+2)(x+3)=0(x + 2)(x + 3) = 0.

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Once we have the equation factored, we apply the . This mathematical rule states that if the product of two or more factors is zero, then at least one of the factors must be zero. By setting each individual factor to zero (x+2=0x + 2 = 0 and x+3=0x + 3 = 0), we easily find our two solutions: x=2x = -2 and x=3x = -3.

Answer: x = 3 and x = 4

Not quite

It is a very common trap to grab the numbers straight from the binomials, but let's look closely at what the zero product property is actually asking us to do. When we write (x+3)(x+4)=0(x + 3)(x + 4) = 0, we are looking for the values of xx that make the entire equation equal to zero. To make the first part, x+3x + 3, equal to zero, we must solve the equation x+3=0x + 3 = 0, which actually requires subtracting 33 from both sides, giving us x=3x = -3.

Always remember that the solutions (or roots) will have the opposite sign of the numbers inside the factored binomials when the coefficient of x is 1.

Let's look at another quick example. If we factor an equation and end up with (x5)(x+2)=0(x - 5)(x + 2) = 0, we set each part to zero. For the first binomial, we solve x5=0x - 5 = 0, which gives x=5x = 5. For the second, we solve x+2=0x + 2 = 0, which gives x=2x = -2. The signs flip because we are isolating the variable on one side of the equation.


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