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Algebraic Generalisation

From Numbers to Symbols

In arithmetic, you work with specific numbers. For example, $3 + 5 = 8$. This is always true. Algebra takes a step back. Instead of just using numbers, we use symbols, usually letters, to represent numbers. This lets us describe relationships and patterns in a more general way.

Think about the cost of a few cinema tickets. If one ticket is £12, two tickets are 2×122 \times 12, and three are 3×123 \times 12. We can generalise this. If the cost of one ticket is cc and you buy nn tickets, the total cost is n×cn \times c. In algebra, we usually drop the multiplication sign to keep things tidy. We write it as ncnc. This is called an algebraic expression.

Variable

noun

A symbol, typically a letter, that represents a quantity that can change or take on different values. In the expression ncnc, both nn and cc are variables.

There are a few conventions to remember. We write the number before the letter (e.g., 4x4x not x4x4). When multiplying a variable by itself, like y×yy \times y, we use index notation: y2y^2. These small rules make expressions easier for everyone to read and understand. An expression is a collection of terms with no equals sign, whereas an equation sets two expressions equal to each other.

Building and Tidying Expressions

Often, we build expressions from worded problems or patterns. Imagine you're buying snacks. A drink costs dd pounds and a bag of popcorn costs pp pounds. If you buy 3 drinks and 2 bags of popcorn, the total cost is an expression: 3d+2p3d + 2p.

What if you go back later and buy another drink and 3 more bags of popcorn? The cost for this trip is d+3pd + 3p. The total for both trips is (3d+2p)+(d+3p)(3d + 2p) + (d + 3p). This looks a bit messy. We can tidy it up by collecting ''. These are terms that contain the same variable raised to the same power. Here, 3d3d and dd are like terms, and 2p2p and 3p3p are like terms.

By adding the number parts, called coefficients, we get $4d + 5p$. This simplified expression is much neater and represents the same total cost.

5x+2y3x+4y=2x+6y5x + 2y - 3x + 4y = 2x + 6y

Powers and Brackets

The same laws of indices you know from arithmetic apply to algebra. When variables are involved, these rules help simplify complex expressions.

OperationRuleAlgebraic Example
Multiplicationam×an=am+na^m \times a^n = a^{m+n}x2×x3=x5x^2 \times x^3 = x^5
Divisionam÷an=amna^m \div a^n = a^{m-n}y7÷y4=y3y^7 \div y^4 = y^3
Power of a Power(am)n=amn(a^m)^n = a^{mn}(z3)4=z12(z^3)^4 = z^{12}

Brackets are used to group terms. To get rid of them, we use a process called expanding. For a single bracket, we use the distributive law and multiply the term outside by everything inside.

5(y+2)=5×y+5×2=5y+105(y + 2) = 5 \times y + 5 \times 2 = 5y + 10

When we have two brackets multiplied together, like (x+3)(x+4)(x+3)(x+4), we need to make sure every term in the first bracket multiplies every term in the second one. A common way to organise this is the grid method.

By adding the terms from the grid (x2+4x+3x+12x^2 + 4x + 3x + 12) and collecting like terms, we get the expanded expression: x2+7x+12x^2 + 7x + 12.

Working Backwards with Factors

Factorising is the reverse of expanding. Instead of removing brackets, we put them back in. The simplest method is to find the highest common factor (HCF) of all the terms in the expression.

Consider the expression 6x+96x + 9. What is the biggest number that divides into both 6x6x and 99? The answer is 3. This is our highest common factor.

We place the HCF outside a set of brackets. Then, we figure out what needs to go inside the brackets by dividing each original term by the HCF. This process is called ''.

6x÷3=2x9÷3=3\begin{aligned} 6x \div 3 &= 2x \\ 9 \div 3 &= 3 \end{aligned}

So, the factorised form is $3(2x + 3)$. You can always check your answer by expanding the brackets back out. If you get the expression you started with, you've done it correctly.

Ready to test your skills? Let's see how well you can build, simplify, and manipulate these new expressions.

Quiz Questions 1/7

Which of the following is an algebraic expression?

Quiz Questions 2/7

A taxi journey costs a flat fee of £3 plus £2 for every mile travelled. If 'm' represents the number of miles, what is the expression for the total cost?

Being able to move smoothly between words, symbols, and different forms of expressions is the foundation of algebra. It's a powerful tool for describing the world and solving problems.