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Introduction to Integration

The Other Side of Change

We've seen that differentiation is all about finding the rate of change. If you have a function that describes a car's position, its derivative gives you the car's velocity at any instant. It's like having a movie and pausing it to see exactly how fast something is moving at that one moment.

But what if you have the opposite problem? What if you know the car's velocity at every moment and want to figure out the total distance it has traveled? This process of adding up all the tiny changes to find the whole is called integration. It's the reverse of differentiation.

Integral

noun

A mathematical object that can be interpreted as an area or a generalization of an area. It represents the accumulation of a quantity.

Visually, one of the most common ways to think about an integral is as the area under a curve. Imagine plotting a function on a graph. The integral over a certain interval gives you the exact area of the shape bounded by the function's curve, the x-axis, and the start and end points of the interval.

Lesson image

Two Kinds of Integrals

Integration comes in two main flavors: indefinite and definite.

An indefinite integral is the most general form of the reverse derivative, often called the antiderivative. When we differentiate a function, any constant term disappears. For example, the derivative of x2+5x^2 + 5 is 2x2x. The derivative of x2100x^2 - 100 is also 2x2x. So, if we want to go backward from 2x2x, what was the original function? We don't know the constant.

To account for this, we add a constant of integration, written as CC. The indefinite integral of 2x2x is x2+Cx^2 + C. The notation looks like this:

2xdx=x2+C\int 2x \,dx = x^2 + C

The \int is the integral sign, and dxdx indicates that we are integrating with respect to the variable xx.

A definite integral, on the other hand, calculates the accumulated value over a specific range. It gives us a concrete number representing the area under the curve between two points, say from aa to bb. Since we're calculating the change between two points, the constant CC cancels out and isn't needed.

abf(x)dx\int_{a}^{b} f(x) \,dx

This represents the area under the curve of f(x)f(x) from x=ax=a to x=bx=b.

The Fundamental Theorem

The deep connection between differentiation (finding slopes) and integration (finding areas) is spelled out by the Fundamental Theorem of Calculus. It's a cornerstone of mathematics for a reason.

The theorem has two parts, but the main idea is this: differentiation and integration are inverse operations. They undo each other. If you integrate a function and then differentiate the result, you get back the original function you started with.

The Fundamental Theorem of Calculus links derivatives and integrals in a beautiful symmetry, showing that integration and differentiation are inverse processes.

This theorem is what allows us to calculate definite integrals easily. To find the area under the curve of f(x)f(x) from aa to bb, we just need to find its antiderivative, let's call it F(x)F(x), and then calculate F(b)F(a)F(b) - F(a). No more slicing the area into infinite tiny rectangles!

Basic Integration Rules

Just like with derivatives, there are rules to make finding integrals easier. The most basic one is the power rule, which is the reverse of the power rule for differentiation.

To find the integral of xnx^n, you increase the exponent by one and then divide by the new exponent.

xndx=xn+1n+1+C(for n1)\int x^n \,dx = \frac{x^{n+1}}{n+1} + C \quad (\text{for } n \neq -1)

Let's try it with an example. To integrate x3x^3, we raise the power from 3 to 4, then divide by 4.

x3dx=x44+C\int x^3 \,dx = \frac{x^4}{4} + C

You can check this by differentiating the result. The derivative of x44+C\frac{x^4}{4} + C is indeed x3x^3.

Another simple rule involves constants. You can pull a constant multiplier out of the integral, just like with derivatives.

kf(x)dx=kf(x)dx\int k \cdot f(x) \,dx = k \int f(x) \,dx

Example: To find 5x2dx\int 5x^2 \,dx, we can treat it as 5x2dx5 \int x^2 \,dx. Using the power rule on x2x^2 gives x33\frac{x^3}{3}. So the final answer is 5x33+C5 \cdot \frac{x^3}{3} + C, or 5x33+C\frac{5x^3}{3} + C.

These basic rules are the first steps toward solving a huge range of problems that involve accumulation and summing things up.

Quiz Questions 1/5

If a function v(t) describes a car's velocity at time t, what does the integral of v(t) represent?

Quiz Questions 2/5

What does a definite integral, such as abf(x)dx\int_{a}^{b} f(x) \,dx, typically represent visually on a graph?