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Advanced Polynomial Functions

Dividing Polynomials

When you need to find the factors of a high-degree polynomial, you can't always use simple factoring methods. A more powerful tool is polynomial division. It works just like the long division you learned in elementary school, but with variables and exponents.

Let's say we want to divide the polynomial 2x33x2+4x52x^3 - 3x^2 + 4x - 5 by x2x - 2. We set it up like a standard division problem.

        2x² +  x  + 6
      ________________
x - 2 | 2x³ - 3x² + 4x - 5
      -(2x³ - 4x²)
      ____________
            x² + 4x
          -(x² - 2x)
          _________
                 6x - 5
               -(6x - 12)
               ________
                      7

The process involves dividing the leading term of the dividend by the leading term of the divisor, multiplying the result by the entire divisor, and then subtracting. You repeat this process until the degree of the remainder is less than the degree of the divisor. Here, the quotient is $2x^2 + x + 6$ and the remainder is 7.

For the special case of dividing by a linear factor like $(x-c)$, there’s a faster method called synthetic division that skips writing out all the variables.

The Remainder and Factor Theorems

Polynomial division leads to a couple of incredibly useful theorems. The division process can be expressed as an equation:

Dividend = (Divisor) × (Quotient) + Remainder

When we divide a polynomial P(x)P(x) by (xc)(x-c), we get: P(x)=(xc)Q(x)+RP(x) = (x-c) \cdot Q(x) + R

Here, Q(x)Q(x) is the quotient polynomial and RR is the constant remainder. The Remainder Theorem gives us a shortcut to find RR. It states that if you divide a polynomial P(x)P(x) by (xc)(x-c), the remainder is simply P(c)P(c). If we plug cc into the equation above, the (xc)(x-c) term becomes zero, leaving us with P(c)=RP(c) = R.

This has a powerful consequence. If the remainder RR is 0, it means (xc)(x-c) divides P(x)P(x) perfectly. This is the core of the — if P(c)=0P(c)=0, then (xc)(x-c) is a factor of P(x)P(x). This gives us a direct way to test for factors without performing the full division.

Finding Potential Roots

The Factor Theorem is great if you already have a root cc to test. But how do you find potential roots in the first place? Guessing randomly isn't efficient for a high-degree polynomial.

This is where the Rational Root Theorem comes in. It provides a complete list of all possible rational roots for a polynomial with integer coefficients. It doesn't guarantee any of them will actually be roots, but it narrows down the search space considerably.

Possible Rational Roots=Factors of the constant termFactors of the leading coefficientPossible\ Rational\ Roots = \frac{\text{Factors of the constant term}}{\text{Factors of the leading coefficient}}

Let's apply this to P(x)=2x3x24x+2P(x) = 2x^3 - x^2 - 4x + 2.

The constant term is 2. Its factors are ±1,±2\pm1, \pm2. The leading coefficient is 2. Its factors are ±1,±2\pm1, \pm2.

Now we form all possible fractions using these factors:

Factors of constant (p)Factors of leading (q)Possible roots (p/q)
±1,±2\pm1, \pm2±1,±2\pm1, \pm2±11,±21,±12,±22\pm\frac{1}{1}, \pm\frac{2}{1}, \pm\frac{1}{2}, \pm\frac{2}{2}

Cleaning up the list gives us the potential rational roots: ±1,±2,±12\pm1, \pm2, \pm\frac{1}{2}. We can now use the Factor Theorem and synthetic division to test these values one by one.

Graphing Polynomials

The roots of a polynomial tell us where its graph crosses the x-axis. But the behavior of the graph at these intercepts reveals even more information.

This is determined by the multiplicity of a root, which is the number of times its corresponding factor appears in the polynomial. For example, in f(x)=(x2)3(x+1)f(x) = (x-2)^3(x+1), the root x=2x=2 has a multiplicity of 3, and the root x=1x=-1 has a multiplicity of 1.

Finally, the end behavior describes what the function does as xx approaches positive or negative infinity. This is determined entirely by the term with the highest degree, called the leading term.

Consider the leading term axnax^n.

  • If the degree nn is even, the graph's ends will point in the same direction (both up or both down).
  • If the degree nn is odd, the ends will point in opposite directions.
  • The sign of the leading coefficient aa determines whether they point up (a>0a>0) or down (a<0a<0).

By combining information about roots, multiplicity, and end behavior, you can create an accurate sketch of any polynomial function without needing to plot dozens of points.

Quiz Questions 1/6

According to the Remainder Theorem, what is the remainder when the polynomial P(x)=2x33x2+4x5P(x) = 2x^3 - 3x^2 + 4x - 5 is divided by (x2)(x-2)?

Quiz Questions 2/6

If you are told that for a polynomial P(x)P(x), P(5)=0P(5) = 0, what can you conclude based on the Factor Theorem?

These theorems and techniques provide a systematic way to analyze and solve high-degree polynomial equations, moving far beyond the capabilities of basic factoring.