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Factoring and Rational Expressions

Factoring to Simplify

Factoring is the process of breaking an expression into a product of simpler expressions. Think of it like finding the ingredients that were multiplied together to create a finished dish. For polynomials, this means rewriting them as a product of their factors. This skill is your primary tool for simplifying complex algebraic fractions, known as rational expressions.

Rational Expression

noun

A fraction in which the numerator and the denominator are both polynomials. Just like a rational number is a ratio of two integers, a rational expression is a ratio of two polynomials.

Let's start with trinomials, which are polynomials with three terms, typically in the form ax2+bx+cax^2 + bx + c. When a=1a=1, we look for two numbers that multiply to cc and add up to bb. For example, to factor x2+7x+12x^2 + 7x + 12, we need two numbers that multiply to 12 and add to 7. Those numbers are 3 and 4.

So, x2+7x+12=(x+3)(x+4)x^2 + 7x + 12 = (x+3)(x+4).

When aa is not 1, the process is slightly more involved. For an expression like 2x2+7x+32x^2 + 7x + 3, we look for two numbers that multiply to a×ca \times c (which is 2×3=62 \times 3 = 6) and add to bb (which is 7). The numbers are 6 and 1. We use these to split the middle term:

2x2+6x+x+32x^2 + 6x + x + 3

Now, we factor by grouping. We take the greatest common factor from the first two terms and the last two terms.

2x(x+3)+1(x+3)2x(x+3) + 1(x+3)

Since both parts share the factor (x+3)(x+3), we can pull it out, leaving us with our final factored form.

(2x+1)(x+3)(2x+1)(x+3)

Special Factoring Formulas

Some polynomial forms appear so often that it's worth memorizing their factoring patterns. These are shortcuts that save you time and prevent errors. The most common are the difference of squares, the sum of cubes, and the difference of cubes.

Formula NamePatternExample
Difference of SquaresA2B2=(AB)(A+B)A^2 - B^2 = (A-B)(A+B)x29=(x3)(x+3)x^2 - 9 = (x-3)(x+3)
Sum of CubesA3+B3=(A+B)(A2AB+B2)A^3 + B^3 = (A+B)(A^2 - AB + B^2)y3+8=(y+2)(y22y+4)y^3 + 8 = (y+2)(y^2 - 2y + 4)
Difference of CubesA3B3=(AB)(A2+AB+B2)A^3 - B^3 = (A-B)(A^2 + AB + B^2)27z31=(3z1)(9z2+3z+1)27z^3 - 1 = (3z-1)(9z^2 + 3z + 1)

Recognizing these patterns is key. When you see two perfect squares separated by a minus sign, you should immediately think 'difference of squares'. Notice there is no 'sum of squares' formula for real numbers; an expression like x2+4x^2 + 4 is considered a prime polynomial because it cannot be factored further using real coefficients.

Factoring is a powerful algebraic problem solution pathway, particularly useful for simplifying expressions, solving quadratic equations, and working with rational expressions.

Operations on Rational Expressions

Now we can apply these factoring skills to rational expressions. The main goal is to simplify them by canceling common factors from the numerator and denominator. Think of it as reducing a simple fraction like $6/8$ to $3/4$ by dividing both top and bottom by their common factor, 2.

Consider this rational expression:

x29x2+7x+12\frac{x^2 - 9}{x^2 + 7x + 12}

First, factor the numerator, which is a difference of squares. Then, factor the trinomial in the denominator.

Numerator: x29=(x3)(x+3)x^2 - 9 = (x-3)(x+3) Denominator: x2+7x+12=(x+3)(x+4)x^2 + 7x + 12 = (x+3)(x+4)

Now rewrite the fraction with the factored forms and cancel the common factor, (x+3)(x+3):

(x3)(x+3)(x+4)(x+3)=x3x+4\frac{(x-3)(x+3)}{(x+4)(x+3)} = \frac{x-3}{x+4}

Multiplication and division of rational expressions follow the same rules as simple fractions. For multiplication, you factor everything first, then multiply straight across and cancel any common factors. For division, you invert the second fraction (the divisor) and multiply.

Adding and Subtracting

Addition and subtraction require a common denominator. If you have two expressions, you need to find the (LCD). The LCD is the smallest polynomial that is divisible by each of the denominators.

To find the LCD:

  1. Factor each denominator completely.
  2. List all the unique factors from all denominators.
  3. For each unique factor, take the highest power that it appears in any single denominator.
  4. The LCD is the product of these factors raised to their highest powers.

Let's add these two expressions:

3x2+5x+3\frac{3}{x-2} + \frac{5}{x+3}

The denominators are already factored and have no common factors. So, the LCD is simply their product: (x2)(x+3)(x-2)(x+3). We rewrite each fraction with this new denominator.

3(x+3)(x2)(x+3)+5(x2)(x2)(x+3)\frac{3(x+3)}{(x-2)(x+3)} + \frac{5(x-2)}{(x-2)(x+3)}

Now that they have a common denominator, we can add the numerators:

3(x+3)+5(x2)(x2)(x+3)=3x+9+5x10(x2)(x+3)=8x1(x2)(x+3)\frac{3(x+3) + 5(x-2)}{(x-2)(x+3)} = \frac{3x+9+5x-10}{(x-2)(x+3)} = \frac{8x-1}{(x-2)(x+3)}

The process is the same for subtraction, but be careful to distribute the negative sign to all terms in the second numerator. This is a very common source of error.

Let's see if you can apply what you've learned.

Quiz Questions 1/6

What is the completely factored form of the trinomial x22x15x^2 - 2x - 15?

Quiz Questions 2/6

Which of the following is the correct factorization of 3x2+11x+63x^2 + 11x + 6?

Mastering these factoring techniques is essential. They form the bedrock for solving equations and understanding more complex functions later on.